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x^2+33x-570=0
a = 1; b = 33; c = -570;
Δ = b2-4ac
Δ = 332-4·1·(-570)
Δ = 3369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{3369}}{2*1}=\frac{-33-\sqrt{3369}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{3369}}{2*1}=\frac{-33+\sqrt{3369}}{2} $
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